{"id":1433,"date":"2013-05-31T20:22:58","date_gmt":"2013-05-31T18:22:58","guid":{"rendered":"http:\/\/www.blue-bears.com\/blog\/?p=1433"},"modified":"2014-08-27T14:53:51","modified_gmt":"2014-08-27T12:53:51","slug":"etude-ballon-helium-pour-travaux-en-hauteur","status":"publish","type":"post","link":"http:\/\/www.blue-bears.com\/blog\/?p=1433","title":{"rendered":"Etude Ballon Helium pour travaux en hauteur."},"content":{"rendered":"
Un ballon pour 1 personne (op\u00e9rateur) sans doute position allong\u00e9e.<\/span><\/div>\n
3 point d’encrage (lest \/ Tonne d’eau ?) motoris\u00e9<\/span><\/div>\n
La man\u0153uvre synchrone des moteurs d’ancrage guid\u00e9 par l’op\u00e9rateur sur le ballon g\u00e8re :<\/span><\/div>\n
* la position<\/span><\/div>\n
* l’altitude<\/span><\/div>\n
\u00a0<\/div>\n

<\/p>\n

L’h\u00e9lium apr\u00e8s utilisation\u00a0 est recompress\u00e9 dans une bouteille de service<\/span><\/div>\n
\u00a0<\/div>\n
Volume ballon po 1 op\u00e9rateur \u00e0 100Kg ?<\/span><\/div>\n
http:\/\/fr.wikipedia.org\/wiki\/H%C3%A9lium<\/a><\/span><\/div>\n
Pourquoi ne pas \u00ab\u00a0doper\u00a0\u00bb \u00e0 l\u2019hydrog\u00e8ne ?<\/span><\/div>\n
http:\/\/fr.wikipedia.org\/wiki\/Hydrogene<\/a><\/span><\/div>\n
\u00a0<\/div>\n
\u00a0<\/div>\n
He : 0,08988\u00a0g\u00b7l-1<\/sup><\/span><\/span><\/span><\/div>\n
\u00a0<\/div>\n
Soit 89.88g\/m-3<\/span><\/span><\/div>\n
Air : 1200g\u00b7m-3<\/sup> <\/span><\/span>
\n<\/span><\/div>\n
100 Kg = 100 000g<\/span><\/div>\n
100 Kg + X volume He = X volume Air<\/span><\/div>\n
100 000 + Xm-3*89.88 = Xm-3 * 1200<\/span><\/div>\n
X = 90m-3<\/span><\/div>\n
Sph\u00e9re 90m-3 = V = (4* Pi * R^3)\/3 => R = 2.75m => Diametre = 5.56m<\/span><\/div>\n
\u00a0<\/div>\n
He : 5m3 = 150\u20acHt => 30\u20ac\/m3 => 90m3\/5 = 18 => 2700\u20ac d’He<\/span><\/div>\n
He Phodia : 17\u20ac\/m3 => 94m3 = 1600\u20ac<\/span><\/div>\n
\u00a0<\/div>\n
Poids Ballon 0.41Kg au m3<\/span><\/div>\n
=> traction diminu\u00e9e<\/span><\/div>\n
\u00a0<\/div>\n
http:\/\/www.phodia.com\/documents\/PHODIA-publicite-gonflable-2012.pdf<\/a><\/span><\/div>\n
y = 0.0049×2 + 0.63x – 1.3999<\/span><\/div>\n
x = Volume en m3<\/span><\/div>\n
y = traction totale en Kg<\/span><\/div>\n
X= 94m3 => x = 100Kg<\/span><\/div>\n
Soit Diam\u00e8tre 5.64m<\/span><\/div>\n

Prix : <\/span>Nous vous remercions d’avoir contact PHODIA.Pour faire suite votre demande, veuillez trouver ci-joint notre documentation.Nb: comptez 2560 HT pour un 5 m avec marquages.<\/span><\/p>\n

Gen\u00e8se id\u00e9e : Un type sur une nacelle \u00e0 25 m de haut (skycraper) qui tangue pour nettoyer les carreaux.<\/span><\/div>\n
\u00a0<\/div>\n
Une solution pour :<\/span><\/div>\n
\n